Question

two numbers are respectively 20% and 50% more than the third number. the ratio of two numbers​

Answer 1

Answer:

Let the third number be x.

First number will be =

$x + \frac{20}{100} x \\ \\ = x + 0.2x \\ \\ = 1.2x$

Second number will be =

$x + \frac{50}{100} x \\ \\ = x + 0.5x \\ \\ = 1.5x$

$ratio \: = \frac{1.2x}{1.5x} \\ \\ = \frac{12}{15} = \frac{4}{5}$

Therefore the ratio of numbers = 12 : 15

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Answer 2

Answer:

$\underline \red{\huge \bold{Given:}}$

• two numbers are respectively 20% and 50% more than the third number

$\underline \red{\huge \bold{To \: Find:}}$

• the ratio of two numbers

$\underline \red{\huge \bold{Solution:}}$

$\sf \: Let \: the \: third \: number \: be \: x \\ </strong></p><p><strong>[tex] \sf \: Let \: the \: third \: number \: be \: x \\ \sf \: Then,first \: number \\ = \sf \: 120\%of \: x = \frac{120x}{100} = \frac{6x}{5} \\ \sf \: Second \: Number \: \\ \sf = 150\%of \: x = \frac{150x}{100} = \frac{3x}{2} \\ \sf \: Ratio \: of \: first \: two \: numbers \\ \sf= \frac{6x}{5} : \frac{3x}{2} = 12x : 15x = 4 : 5$