Question

Two numbers are respectively 28% and 25% less than a third number what percenyage is the first of the second

Answer 1

Answer:

Step-by-step explanation:

Let third number is m

first no is 25% less than m , it is m- m/4 =3m/4

second is 20 % less thsn m, it is m-m/5 =4m/5

Let first no is x% of second

3m/4= 4mx/500

x=1500m/16m =1500/16=93.75

ans is 93.75%

Answer 2

SOLUTION

LET THE THIRD NUMBER IS =X

NOW THE first NUMBER IS

$= x(1 - \frac{28}{100} ) \\ = \frac{72x}{100}$

and the second number is

$x(1 - \frac{25}{100} ) \\ = \frac{75x}{100}$

the first number is greater than by

$= \frac{75x}{100} - \frac{72x}{100} \\ = \frac{3x}{100}$

to the second number

and therefore the first number is greater than by the percentage of ...

$= \frac{ \frac{3x}{100} }{ \frac{72x}{100} } \times 100 \\ = \frac{300}{72} \\ = 4.17 \: \: percent$