Question

Two numbers are respectively 40% and 60% more than third member. Find the ration of two numbers?

Answer 1

Answer:

7:8

Step-by-step explanation:

Answer 2

$Let \: the \:third \:number = x$

$Second \:number = 40\% \: more \:than\:x \\= x\Big(\frac{100+40}{100} \Big) \\= x \times\frac{140}{100} \\= \frac{140x}{100} \:--(1)$

$Third \:number = 60\% \: more \:than\:x \\= x\Big(\frac{100+60}{100} \Big) \\= x \times\frac{160}{100} \\= \frac{160x}{100} \:--(2)$

/* According to the problem given */

$\red {ratio} = \frac{Second \: number }{Third \:number } \\= \frac{ \frac{140x}{100}}{\frac{160x}{100}}\\= \frac{140x}{100} \times \frac{100}{160x} \\= \frac{140}{160} \\= \frac{7}{8} \\= 7 : 8$

Therefore.,

$\red {Ratio } \green {= 7 : 8 }$

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