Question

two numbers are respectively 60% and 20% more than a third number second number expressed as a percentage of first is​

Answer 1

Answer:

Step-by-step explanation:

let x , y and z be the numbers.

x = 1.6z and y = 1.2z, then

y / x = 1.2 / 1.6 = 0.75

thus the second number is 75% of the first.

Answer 2

Therefore second number is 75% of first number.

Two numbers are respectively 60% and 20% more than a third number.

We have to express second number as a percentage of first.

Let third number is 100.

a/c to question, first number is 60% more than third number.

∴ first number = 100 + 60% of 100 = 100 + 60 × 100/100 = 160

again, Second number is 20% more than third number.

∴ second number = 100 + 20% of 100 = 100 + 20 × 100/100 = 120

so, first number = 160

second number = 120

let second number is x % of first number

⇒120 = x % × 160

⇒120/160 = x/100

⇒300/4 = x

⇒x = 75 %

Therefore second number is 75% of first number.