Two numbers are such that if 7 is added to first number a number twice the second number is obtained. If 20 is added to the second number is obtained is four times the first number. Find the two number.
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Let the numbers be x and y
if 7 is added to first number a number twice the
second number is obtained.
x+7 = 2y
=> x = 2y - 7
If 20 is added to the second number, number obtained is four times the first number
y+20 = 4x
=> y + 20 = 4(2y - 7)
=> y + 20 = 8y - 28
=> y - 8y = -28 - 20
=> -7y = -48
=> y = 48/7
x = 2y - 7 = 2×(48/7) - 7 = 96/7 - 7 = (96-49)/7 = 47/7
The numbers are 48/7 and 47/7
if 7 is added to first number a number twice the
second number is obtained.
x+7 = 2y
=> x = 2y - 7
If 20 is added to the second number, number obtained is four times the first number
y+20 = 4x
=> y + 20 = 4(2y - 7)
=> y + 20 = 8y - 28
=> y - 8y = -28 - 20
=> -7y = -48
=> y = 48/7
x = 2y - 7 = 2×(48/7) - 7 = 96/7 - 7 = (96-49)/7 = 47/7
The numbers are 48/7 and 47/7
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