Question

Two numbers are such that if 7 is added to first number a number twice the second number is obtained. If 20 is added to the second number is obtained is four times the first number. Find the two number.

Answer 1

Dear see the attachment... Hope u understand..

Answer 2

Let the numbers be x and y

if 7 is added to first number a number twice the
second number is obtained.

x+7 = 2y
=> x = 2y - 7

If 20 is added to the second number, number obtained is four times the first number

y+20 = 4x

=> y + 20 = 4(2y - 7)

=> y + 20 = 8y - 28

=> y - 8y = -28 - 20

=> -7y = -48

=> y = 48/7

x = 2y - 7 = 2×(48/7) - 7 = 96/7 - 7 = (96-49)/7 = 47/7

The numbers are 48/7 and 47/7