Two numbers are such that if 7 is added to the first , a number twice the second number is the obtained. If 20 is added to the second number, is the number obtained is four times the first number. find the two number.
Answers
Answer:
Let the numbers be x and y
if 7 is added to first number a number twice the
second number is obtained.
x+7 = 2y
=> x = 2y - 7
If 20 is added to the second number, number obtained is four times the first number
y+20 = 4x
=> y + 20 = 4(2y - 7)
=> y + 20 = 8y - 28
=> y - 8y = -28 - 20
=> -7y = -48
=> y = 48/7
x = 2y - 7 = 2×(48/7) - 7 = 96/7 - 7 = (96-49)/7 = 47/7
The numbers are 48/7 and 47/7
Step-by-step explanation:
brainliest,plz mark meeee
Answer:
The numbers are (48/7) and (47/7)
Step-by-step explanation:
Let the first number be x and second number be y
Then, According to the Question,
First number + 7 = 2 times the second number
x + 7 = 2 × y
x + 7 = 2y
x = 2y - 7 ----- 1
Similarly, also given,
Second number + 20 = 4 times first number
y + 20 = 4 × x
y + 20 = 4x ----- 2
Substituting eq.1 in eq.2, we get,
y + 20 = 4(2y - 7)
y + 20 = 8y - 28
28 + 20 = 8y - y
48 = 7y
y = 48/7 ----- 3
Substituting eq.3 in eq.1
x = 2(48/7) - 7
x = (96/7) - 7
x = (96/7) - (49/7)
x = (96 - 49)/7
x = (47/7)
Hence,
The numbers are (48/7) and (47/7).
Hope it helped you and believing you understood it....All the best