Question

Two numbers are such that if 7 is added to the first
number, a number twice the second number is
obtained. If 20 is added to the second number,
the number obtained is four times the first number.
Find the two numbers.​

Answer 1

Let the numbers be x and y

if 7 is added to first number a number twice the

second number is obtained.

x+7 = 2y

=> x = 2y - 7

If 20 is added to the second number, number obtained is four times the first number

y+20 = 4x

=> y + 20 = 4(2y - 7)

=> y + 20 = 8y - 28

=> y - 8y = -28 - 20

=> -7y = -48

=> y = 48/7

x = 2y - 7 = 2×(48/7) - 7 = 96/7 - 7 = (96-49)/7 = 47/7

The numbers are 48/7 and 47/7

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Answer 2

Answer:

Hope this is helpful.

Step-by-step explanation:

x= 47/7 ,y= 48/7.

If correct mark as brainliest.