Question

two numbers are such that one number is 42 more than the other number and their average is equal to 40 find the two numbers​

Answer 1

Answer:

Let the second number = x

Then, the first number = x+42

According to the Question, their average is 40.

So ,

Average = (Sum of both numbers)/2

If the second number is x = 19 , then the first number is = x+42 = 19+42 = 61.

The required numbers are 19 and 61.

Step-by-step explanation:

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