Question

two numbers are such that ratio between them is 3 ratio 5 if each is increased by 10, the ratio between the New numbers so formed is 5 ratio 7 find the original number​

Answer 1

Let the nos be denoted by x.
Ratio = 3x : 5x
ATQ....
$\frac{3x + 10}{5x + 10} = \frac{5}{7} \\ = > 21x + 70 = 25x + 50 \\ = > 70 - 50 = 25 x - 21x \\ = > 4x = 20 \\ = > x = 5.$
3x = 3×5 =15
5x = 5×5= 25
The nos are 15 and 25.

Answer 2

Step-by-step explanation:

Let the numbers as x and y

So their ratio:

x/y = 3/5

Cross multiple

5x =3y

x = 3y/5

y = 5x/3

If 10 is added

10+X/ 10+y = 5/7

Cross multiple

70+7x = 50 + 5y

20 +7x = 5y.

Putting the value of X

20+ 7(3y/5) = 5y

Taking LCM

100+ 21y /5 = 5y

100+21y = 25y

100 = 25y-21y

100 = 4y

100/4 = y

25 = y

x = 3y/5

x = 3(25)/5

x = 15

So X = 15 and y = 25