Question

two numbers are such that the ratio between them 3:5.if each is increased by 5,the ratio between the new numbers so formed is 2:3.find the orignal number

Answer 1

Heya,
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✓✓✓ Here is ur answer in the attachment.

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Ankit

Answer 2

Let the two number be x and y,

Then, according to question,
=> 3x = 5y
=> 3x - 5y = 0
=> 2(3x - 5y) = 0
=> 6x - 10y = 0 ...........(i)

And, by increasing each number by 5, we get
=> 3x + 5 / 5y + 5 = 2 / 3
=> 3(3x + 5) = 2(5y + 5)
=> 9x + 15 = 10y + 10
=> 9x - 10y + 15 - 10 = 0
=> 9x - 10y + 5 = 0 ...........(ii)

Using equation (i) & (ii), we get
=> 9x - 10y - (6x - 10y) = -5
=> 9x - 10y - 6x + 10y = -5
=> 3x = 15
=> x = 5

From equation (i) ,
=> 6x - 10y = 0
=> 6×(- 5/3 ) - 10y = 0
=> 2y = 10
=> y = 5

Hence, the first number is 3x = 15
and the second number is 5y = 25