Question

Two numbers are such that the ratio between them is 3;4 .If 16 added to both numbers the ratio between the new numbers so formed is 5;6 Find the original numbers.

Answer 1

Answer:

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Answer 2

Given,

• The ratio between two number is 3:4

To Find,

• Original Numbers = ?

Solution,

Let the two numbers be 3x and 4x.

$\boxed{\bf{\bold{\red{According \ to \ Question :}}}}$

⇒If 16 is added to both numbers then the ratio between the new numbers so formed ratio = 5 :6

$\implies \bold{(3x + 16) : (4x +16) = 5 :6}$

$\implies \bold{\frac{3x + 16 }{4x + 16} = \frac{5}{6}}$

$\implies \bold{6(3x + 16) = 5(4x +16)}$

$\implies \bold{18x + 96 = 20x + 80}$

$\implies \bold{18x - 20x = 80 -96}$

$\implies \bold{-2x = -16 }$

$\implies \bold{x = \frac{-16}{-2}}$

$\implies \boxed{\bold{x = 8}}$

Therefore ,

⇒Original Number are 3x = 3 x 8 = 24 And 4x = 4 x 8 = 32

$\rule{200}2$