Two numbers are such that the ratio between them is 3:5. If each is increased by 10, the
ratio between the new numbers so formed is 5:7. Find the original number
.
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Given :
- Two numbers are such that the ratio between them is 3:5.
- Each is increased by 10.
- The ratio between the new numbers so formed is 5:7.
To find :
- The original number =?
Step-by-step explanation :
Let, two numbers are such that the ratio between them be 3x and 5x.
After increasing 10 in 3x = 3x + 10
After increasing 10 in 5x = 5x + 10
According to the question :
➮ (3x + 10)/(5x + 10) = 5/7
➮ 7(3x + 10) = 5(5x + 10)
➮ 21x + 70 = 25x + 50
➮ 21x - 25x = 50 - 70
➮ -4x = - 20
➮ x = - 20/-4
➮ x = 5.
So, We got the value of, x = 5
Hence,
3x = 3 × 5 = 15
5x = 5 × 5 = 25
Therefore, the original number = 15 and 25.
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