Question

Two numbers are such that the ratio between them is 3:5. if each is increased by 10,the ratio between the new numbers so formed is 5:7. find the original number.​

Answer 1

Answer:

Let the ratio,3:5 be taken as 3x and 5x

BTP,

If the ratios are increased by 10 i.e,

3x+10 and 5x+10

BTP,

3x+10+5x+10=5x+7x

8x+20=12x8x-12x=-20

-4x=-20

x=-20/-4

=5

Therefore,the original ratio 3x and 5x

3x=3×5=15

5x=5×5=25

Answer 2

Answer:

ans is 15 , 25

Step-by-step explanation:

let x and y be tworth numbers

now

Case 1

Two numbers are such that the ratio between them is 3:5

As per conditions

x:y = 3:5

5x = 3y

x = 3y/ 5 - - - - - - - - - -( i )

Case 2

If each number is increase by 10 the ratio between is 5:7

:. (x+ 10) : (y + 10 ) = 5:7

:. 7(x+10 ) = ( y + 10 )

:. 7x + 70 -50 = 5y

:. 7x + 20 = 5y - - - - - - - - - - (ii)

:. put the value of x from equation (i) in (ii)

:. 7 × 3y/ 5 + 20 = 5y

:. 21y +100 / 5 = 5y

:. 21y +100 = 25y

:. 100 = 4y

:. y= 100 / 4

:. y = 25

:. put in equation (i)

:. x = 3 × 25 / 5

:. x = 15