Two numbers are such that the ratio between them is 3:5 if each is increased by 10, the ratio between the new numbers so formed is 5:7 find the original number?
Answers
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Two numbers are such that the ratio between them is 3:5 if each is increased by 10, the ratio between the new numbers so formed is 5:7 find the original number?
To numbers are in the ratio 3:5.
if each number is increased by 10 then the ratio of the new numbers is 5:7.
The original numbers
According to the Question:-
If each number is increased by 10 then the ratio of the new numbers is 5:7.
Value of x is 5.
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◇Solution:
x and y are 2 numbers..
x : y = 3:5
5x = 3y
x = 3y / 5 (1)
according to the problem given,
if each is increased by 10, the ratio between
the new numbers so formed is 5:7
(x + 10 ): (y + 10 ) = 5:7
7( x + 10 ) = (y + 10 ) 5
7x + 70 = 5y + 50
7x + 70 - 50 = 5y
7x + 20 = 5y(2)
substitute x value from equation (1) in (2)
7x 3y/5 + 20 = 5y
( 21y + 100 )/5 = 5y
21y + 100 = 25y
100 = 25y - 21y
100 = 4y
100 / 4 = y
25 = y
Therefore,
y = 25
put y = 25 in equation (1), we get
x = 3 × 25 / 5
x = 3 × 5
x = 15
Original numbers are x and y