Question

Two numbers are such that the ratio between them is 3:5. If each is increased by 10, the
ratio between the new numbers so formed is 5: 7. Find the original numbers
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Answer 1

Answer:

nswer:

Answer:

Given :-

Two numbers are such that the ratio between them is 3:5.

Each is increased by 10, the ratio between the new numbers are 5:7.

To Find :-

What is the original number.

Solution :-

Let, the first number be 3x

And, the second number be 5x

Each number is increased by 10, the ratio between the new numbers are 5:7.

According to the question,

⇒ \dfrac{3x + 10}{5x + 10}

5x+10

3x+10

= \dfrac{5}{7}

7

5

By doing cross multiplication we get,

⇒ 7(3x + 10) = 5(5x + 10)

⇒ 21x + 70 = 25x + 50

⇒ 21x - 25x = 50 - 70

⇒ - 4x = - 20

⇒ x = \dfrac{\cancel{- 20}}{\cancel{- 4}}

−4

−20

➠ x = 5

Hence, the required number are,

✦ First number = 3x = 3(5) = 15

✦ Second number = 5x = 5(5) = 25

\therefore∴ The number are 15 and 25 .

\begin{gathered}\\\end{gathered}

Let's Verify :-

⇒ 7(3x + 10) = 5(5x + 10)

Put x = 5

⇒ 7(15 + 10) = 5(25 + 10)

⇒ 7(25) = 5(35)

➠ 175 = 175

➥ LHS = RHS

Hence, Verified.

Answer 2

Answer:

refer to the attachment