two numbers are such that the ratio between them is 5 ratio 8 if each is increased by 10 the ratio between the numbers become 7 ratio 10 find the numbers
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Let the two numbers are x and y
then,
x/y = 3/5
x=(3y) /5. ......(1)
also,
(x+10)/(y+10) = 5/7
7(x+10)=5(y+10)
7x = 5y+50-70=5y-20
put the value of x from eq. (1)
7(3y/5) =5y - 20
21y =25y - 100
25y-21y = 100
y = 100/4
y =25
put the value of y in eq.(1)
x = (3×25)/5
x=15
hence , the numbers are 15 and 25
then,
x/y = 3/5
x=(3y) /5. ......(1)
also,
(x+10)/(y+10) = 5/7
7(x+10)=5(y+10)
7x = 5y+50-70=5y-20
put the value of x from eq. (1)
7(3y/5) =5y - 20
21y =25y - 100
25y-21y = 100
y = 100/4
y =25
put the value of y in eq.(1)
x = (3×25)/5
x=15
hence , the numbers are 15 and 25
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harshdubey52:
no the ans=25 40
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0
Let 1st no.=X
Let 2nd no.=y
Ratio=5/8
So,x/y=5/8
x=5y/8...(1)
Now,
x+10/y+10=7/10...(2)
Put eq no.(1) in (2)
(5y/8+10)/(y+10)=(7/10)
5y+80/8=7y+70/10
50y+800=56y+560
56y-50y=800-560
6y=240
y=40
So,
As x=5y/8
Put y=40
x=5×40/8
x=25
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