Question

Two numbers are such that, the sum of the squares of 2 numbers is 113 and their products is 56,twice the sum of the two number is_​

Answer 1

Answer:

sum= 15

Step-by-step explanation:

given $a^{2}$ + $b^{2}$ = 113

and a X b = 56

we find factors of 56

we figure out, $7^{2}$ + $8^{2}$ is 113 and their product is also 56

and we have to find a + b

we got a= 7 b=8

so a+b = 7+8 = 15