Two numbers are the ratio 5:6 if 8 is subtracted from each of the numbers the ratio becomes 4:5 find the number
Answers
Two numbers are in the ratio 5:6.
Let one number be 5M and other number be 6M.
If 8 is subtracted from each number then the ratio becomes 4:5.
Now,
New numbers -
- One number = 5M - 8
- Other number = 6M - 8
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∴ One number = 5M
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∴ Other number = 6M
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•°•
Smaller Number = 40
Greater Number = 48
Given :
- Two numbers are the ratio 5:6
- If 8 is subtracted from each of the numbers the ratio becomes 4:5
To find :
- The numbers
Solution :
Let x be the common multiple of the ratio 5:6
•°• Greater Number = 6x
Smaller Number = 5x
- 8 is subtracted from each of the numbers the ratio becomes 4:5
•°• Greater Number = 6x - 8
Smaller Number = 5x - 8
Constituting it mathematically,
=
Cross multiplying,
•°• x = 8
Substitute x = 8 in the values of the ratio,
•°• Smaller number = 5x = 5 (8) = 40
Greater Number = 6x = 6(8) = 48
For first case :
- Two numbers are the ratio 5:6
Greater Number = 48
Smaller Number = 40
Ratio = 5:6
=
Dividing LHS by 8,
=
LHS = RHS.
For second case :
- 8 is subtracted from each of the numbers the ratio becomes 4:5
Greater Number = 48 - 8 = 40
Smaller Number = 40 - 8 = 32
Ratio = 4:5
=
Dividing LHS by 8,
=
LHS = RHS.
Hence Substantiated.