Question

two numbers differ by 3 and their product is 504 find the numbers​

Answer 1

$let \: to \: numbers \: be \: x \: \\ and \:( x \: + 3) \\ \\ according \: to \: given \: condition \\ \\ x(x + 3) = 504 \\ {x}^{2} + 3x = 504 \\ {x}^{2} + 3x - 504 = 0 \\ \\ {x}^{2} + 24x - 21x - 504 = 0 \\ \\ x(x + 24) - 21(x + 24) = 0 \\ \\ (x -21) = 0 \\ or(x + 24) = 0 \\ x = 21or \: x = - 24 \\ \\ \\ \\ it \: will \: definetly \: help \: u...$

it will definitely help u....