two numbers differ by 3 and their product is 504 find the numbers
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Hi ,
Let one number = x
Second number = x - 3
Product = 504
x( x - 3 ) = 504
x² - 3x - 504 = 0
x² - 24x + 21x - 24 × 21 = 0
x( x - 24 ) + 21( x - 24 ) = 0
( x - 24 ) ( x + 21 ) = 0
Therefore ,
x - 24 = 0 or x + 21 = 0
x = 24 or x = - 21
1 ) if x = 24 second number is 21
2 ) if x = -21 , second number is -24
I hope this helps you.
:)
Let one number = x
Second number = x - 3
Product = 504
x( x - 3 ) = 504
x² - 3x - 504 = 0
x² - 24x + 21x - 24 × 21 = 0
x( x - 24 ) + 21( x - 24 ) = 0
( x - 24 ) ( x + 21 ) = 0
Therefore ,
x - 24 = 0 or x + 21 = 0
x = 24 or x = - 21
1 ) if x = 24 second number is 21
2 ) if x = -21 , second number is -24
I hope this helps you.
:)
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