Question

Two numbers differ by 3 and their product is 504 find the numbers

Answer 1

i've dropped an attchment... hope it helps!

Answer 2

Assume two numbers are x (bigger number) and y (smaller number), then:
$x-y=3$ and $x\times y = 504$

Substitute $x=3+y$ into the second equation above:
$(y+3)\times y=504$
$y^2+3y-504=0$
$(y-21)(y+24)=0$
Thus, $y=21 \,or\, y=-24$

Substitute into any one of the first equations to find x:
$y=21$, then: $x-21=3$, $x=24$ (initial assumption holds, x>y)
$y=-24$, then: $x-(-24)=3$, $x=-21$ (initial assumption holds, x>y)