Question

two numbers differ by 3 and their product is 54. find the numbers.

Answer 1

Hii friend,

Let the first number be X

The the other number = (X-3)

According to question,

Product of two numbers=54

Therefore,

(X-3) × X = 54

X²-3X = 54

X²-3X-54 = 0

X²-9X+6X -54 = 0

X(X-9) +6(X-9) = 0

(X-9) (X+6) = 0

X -9 = 0 OR X +6 = 0

X = 9 or X = -6

Therefore,

First Number = 9

And,

The second number = -6

HOPE IT WILL HELP YOU.... :-)

Answer 2

Buddy here is ur answer....


Let the number be x
and the 2nd number =x-3

ATQ,
we have ,
x(x-3)=54

x^2-3x-54=0
x^2 -9x+6x-54=0
x(x-9)+6(x-9)=0
(x-9)(x+6)=0

Hence x=9,-6