Question

Two numbers differ by 3.The sum of the greater number and twice the smaller number is 15.Find the smaller number.

Answer 1

Answer:

The smaller number is 4

Step-by-step explanation:

Let the two numbers be "x" and "y" where "x" is the greater one.

ATQ, the two numbers differ by 3

=> x - y = 3 ........(i)

ATQ, sum of greater number and twice the smaller number is 15

=> x + 2y = 15 .........(ii)

Multiply (i) by 2

=> 2x - 2y = 6 ..........(iii)

Add (ii) and (iii)

=> 3x = 21

=> x = 7

=> y = 4 ........Using (i)

The two numbers are 4 and 7

Answer: The smaller number is 4

Verification:

* Difference is 3 (7 - 4 = 3) √

* 7 + 2(4) = 15 √

Conditions given are satisfied, hence verified.

Answer 2

Step-by-step explanation:

solution

let the two numbers be X and Y .

X>Y

case1

X-Y=3............(1)×2

X+2Y=15.........(2)

Addingequation (2) and equation (1) we get,

X+2Y=15

2X-2Y=6

....................

3x=21

x=21/3

X=7

put the value of X=7 in equation (2),

X+2y=15

7+2y=15

2y=15-7

2y=8

y=8/2

y=4

the value of smaller number is 4.