Two numbers differ by 3. The sum of their reciprocals is 7 / 10. Find the numbers
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The num diffrent by 3 is 4 and
reciprocol of 7/10is
10/7ans
reciprocol of 7/10is
10/7ans
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let the nos. be x and y
Given, x-y=3. x=y+3
1/x+1/y=7. or 1/(y+3)+1/y=7/10
1/(y+3)=7/10-1/y
1/(y+3)=(7-10y)/10
1×10=(y+3)(7-10y)
10=7y-10y*y+21-30y
23y*y+10y-11=0
Given, x-y=3. x=y+3
1/x+1/y=7. or 1/(y+3)+1/y=7/10
1/(y+3)=7/10-1/y
1/(y+3)=(7-10y)/10
1×10=(y+3)(7-10y)
10=7y-10y*y+21-30y
23y*y+10y-11=0
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