Question

Two numbers differ by 3 the sum of twice the smaller number and thrice the greater number is 19 reoresent the situation algebrically

Answer 1

Answer:

equation no. 1 = x-y=3

equation no. 2= 3x+2y=19

value of x=5

value of y=2

Step-by-step explanation:

let one of the number be=x

and another number be=y

and, let x>y

so as they differ by three the equation will be

x-y=3------------(equation no. 1)

similarly, sum of twice the small and thrice the greater no. is 19 so the equation will be

3x+2y=19----------(equation no. 2)

now, multiply equation no. 1 by 2 on both sides

2(x-y) =2(3)

2x-2y=6

add both equations

3x+2y+2x-2y=19+6

5x=25

x=25/5=5

now, put value of x in equation no. 1 to get the value of y

so, x-y=3

5-y=3

y=5-3=2

value of x=5

value of y=2

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Answer 2

Step-by-step explanation:

I hope it will help you......