Two numbers differ by 3. The sum of twice the smaller number and thrice the greater number is 19. Find the numbers.
Answers
Answered by
3
Hi there!
Let the two numbers be x and y such that x > y.
ATQ,
x - y = 3
∴ x = y + 3. ----(i)
2y + 3x = 19. ----(ii)
Substitute value of x in eqn. (ii)
2y + 3 (y + 3) = 19
2y + 3y + 9 = 19
5y = 19 - 9
5y = 10
y = 10 / 5 = 2
Thus,
x = 2 + 3 = 5
Hence, The required answer is :-
The two numbers are x = 5 and y = 2
hope it helps! :)
Let the two numbers be x and y such that x > y.
ATQ,
x - y = 3
∴ x = y + 3. ----(i)
2y + 3x = 19. ----(ii)
Substitute value of x in eqn. (ii)
2y + 3 (y + 3) = 19
2y + 3y + 9 = 19
5y = 19 - 9
5y = 10
y = 10 / 5 = 2
Thus,
x = 2 + 3 = 5
Hence, The required answer is :-
The two numbers are x = 5 and y = 2
hope it helps! :)
Answered by
0
hi friend!
let the two numbers be a and b such that a>b.so equation 1 is a- b=3.so a=b+3.equation 2 will be 2b+3a=19.replace the value of a in equation 2.
now we get
2b+3(y+3)=19
2b+3b+9=19
5b=19-9
5b=10
b=2
so a=2+3=5
and a=5 and b=2
hope my answer helps you
keep smiling
let the two numbers be a and b such that a>b.so equation 1 is a- b=3.so a=b+3.equation 2 will be 2b+3a=19.replace the value of a in equation 2.
now we get
2b+3(y+3)=19
2b+3b+9=19
5b=19-9
5b=10
b=2
so a=2+3=5
and a=5 and b=2
hope my answer helps you
keep smiling
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