Two numbers differ by 3 the sum of twice the smaller number and thrice the greater number is 19 find the number ?
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Hi sanskruti ,
answer :=
let suppose,
the two no.are x and y
X - Y= 3 ........eq n 1st.
2 y + 3x = 19. ...........eq n 2nd.
multiply eq n 1st by 3
2 x - 2 y = 6 .........eq n 3rd.
add eq n 3rd and 2nd
= 5x = 25
x = 5
put x = 5 in eq n 1st
x - y = 3
so 5 - y = 3
5 - 3 = y
2 = y
ans :=
X = 5
Y = 2
answer :=
let suppose,
the two no.are x and y
X - Y= 3 ........eq n 1st.
2 y + 3x = 19. ...........eq n 2nd.
multiply eq n 1st by 3
2 x - 2 y = 6 .........eq n 3rd.
add eq n 3rd and 2nd
= 5x = 25
x = 5
put x = 5 in eq n 1st
x - y = 3
so 5 - y = 3
5 - 3 = y
2 = y
ans :=
X = 5
Y = 2
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0
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