Two numbers differ by 4 and their product is 192. Find the numbers.
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The two numbers would be 16 and 12
Step-by-step explanation:
Let the numbers be x and x+4, then we get:
x (x + 4) = 192
x² + 4x - 192 = 0
Factors of -192 are -16 and +12.
So x² + 4x - 192 = 0 can be written as:
x² + 12x -16x - 192 = 0
x (x +12) -16 (x + 12) = 0
(x -16) (x +12) = 0
So the factors are (x -16) and (x +12).
If (x -16) = 0, then x = +16
If (x +12) = 0, then x = -12
Hence solved.
X = 16, -12
So the two numbers would be 16 and 12.
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