Question

two numbers differ by 4 and their product is 192 find the numbers​

Answer 1

$\bf 1st \: No. = x \\ \\</p><p>\bf 2nd\: No. = y$

1st case :

$\bf x - y = 4 \\ \\ \bf x = y + 4$

2nd case :

$\bf x \times y = 192$

Put x value in 2nd case

$\bf (y + 4) \times y = 192 \\ \\ \bf {y}^{2} + 4y - 192 = 0 \\ \\ \bf {y}^{2} + 16y - 12y - 192 = 0 \\ \\ \bf y(y + 16) - 12(y + 16)=0 \\ \\ \bf (y - 12)(y + 16)=0 \\ \\ \large\underline{\boxed{\bf \orange{ y = 12}}}$

Put y value in 1st case

$x = y + 4 \\ \\ x = 12 + 4 \\ \\ \large\underline{\boxed{ \bf \green{ x = 16}}}$

$\bf \blue{ Two \: numbers \: are \: 16 \: and \: 12}$