Math, asked by srikrishnkant, 9 months ago


Two numbers differ by 40. When each number is decreased by the bigger becomes thrice
the lesser number. Find the numbers?​

Answers

Answered by singhpinki195
3

Here is your answer

let \: the \: two \: numbers \: be \: \: x \: and \: y \\  \\ then \: x  - y = 40  \\ let \: x \: be \: the \: bigger \: number and \: y \: be \: the \: smaller \: number \\ y - x = 3y \\  - 2y = x \\ y =  \frac{ - x}{2}  \\ put \: in \: equation \: 1 \\   \frac{ x}{2}  + x = 40 \\  \frac{2x + x}{ 2} = 40 \\  \frac{3x}{2}   = 40 \\  \\ x =  \frac{80}{3}  \\ put \: the \: vaue \: of \: x \: in \: second \: equation \\ y =   \frac{ - x}{2}  \\ y =  \frac{ - 40}{3}  \\ hence \: the \: two \: number \: are \:  \frac{80}{3} and \:  \frac{ - 40}{3}

Hope you like my answer mark brainliest please.

Answered by Kanagaraju
0

Answer:

two numbers 20 and 60

Step-by-step explanation:

let A is small number

let B is larger number

B- A =40

B : A = 3: 1

Applying ratio on equation

3x- x = 40

2x =40

x= 20

A = 20, B = 60

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