Two numbers differ by 5 and there product is 336 then the sun of 2 numbers is??
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let the two numbers be x and x+5 since they differ by 5
A2Q, product of two numbers = 336
so, x * [ x+5 ] = 336
x²+5x = 336
Step 1: Subtract 336 from both sides.
x²+5x−336=336−336
x²+5x−336=0
Step 2: Factor left side of equation.
(x−16)(x+21)=0
Step 3: Set factors equal to 0.
x−16=0 or x+21=0
x=16 or x=−21
so the numbers are either 16 and 21 or -16 and -21
hope it helps
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