Two numbers differ by 5. If their product is 336.the sume of the number is what
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let the numbers are x and y.
according to question,
x-y=5 and xy=336
[x+y]^2=[x-y]^2+4xy
[x+y]^2=5^2+336*4
[x+y]^2=25+1344
[x+y]^2=1369
[x+y]=37
THE ANSWER WILL BE 37.
according to question,
x-y=5 and xy=336
[x+y]^2=[x-y]^2+4xy
[x+y]^2=5^2+336*4
[x+y]^2=25+1344
[x+y]^2=1369
[x+y]=37
THE ANSWER WILL BE 37.
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