Two numbers differ by 5. If their product is 336, then sum of two number is
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Let the first number = x
second number = x+5
therefore, according to the question
x (x+5) = 336
x^2 + 5x = 336
x^2 + 5x - 336 = 0
Now by quadratic formula
D = b^2 - 4ac
= 5^2 - 4x1x -336
=25 + 1344
= 1369
Now -b +- √D /2
= -5 +- 37 / 2 OR = -42/2
= 32 / 2 = -24
= 16
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