Question

two numbers differ by 5, if their product is 336 then what is the sum of two numbers

Answer 1

Let the first number be a

Second number = a - 5

According to question,

a ( a - 5) = 336

=> a^2 - 5a - 336 = 0

=> a^2 - 21a + 16a - 336 = 0

=> a ( a - 21) + 16(a - 21) = 0

=> (a - 21) (a + 16) = 0

a = 21 and - 16

Neglecting negative value, we get

a = 21

First number = 21

Second number = 21 - 5 = 16

Sum of numbers = 21 +16 = 37