Question

Two numbers differ by 5. The sum of thrice the smaller number and twice the greater number is 20 .Find the smaller number .​

Answer 1

Answer:

(a+b)²=(a-b)²+4ab

So according to this question let the first number be a and the second number be b then

a-b=5

a×b=33

Then

Put the values in the identity then solve this

(a+b)²=(a-b)²+4ab

(a+b)²=(5)²+4(336)

(a+b)²=25+1344

(a+b)²=1369

a+b=√1369

a+b=37

Then it is solved but if you want the value then:-

Let take first number as x and second number will be x+5

So a=x and b=x+5

Then

a+b=37 so

Then

x+x+5=37

2x+5=37

2x=37–5

2x=32

x=32÷2

x=16

then x+5= 16+5=21

So then first Numbers is 21 and second number is 16.

And if you have still doubt in my solution then ask me .