Question

Two numbers differ by 9. Four times the bigger exceeds the square of the smaller by 4​

Answer 1

let the two no.s be x and y.

and x be the bigger one.

so.= x-y =9----------------(1)

= 4(x)-(y)^2 =2------(2)

now just solve the two equations..

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Answer 2

The numbers can be (17,8) and (5,-4).

Step-by-step explanation:

Given : Two numbers differ by 9. Four times the bigger exceeds the square of the smaller by 4​.

To find : The numbers ?

Solution :

Let the one number be 'x'.

The other number be 'y'.

Two numbers differ by 9.

i.e. $x-y=9$ ....(1)

Four times the bigger exceeds the square of the smaller by 4​.

$4x-y^2=4$ ....(2)

Solving (1) and (2),

Substitute the value of x from (1) in (2),

$4(9+y)-y^2=4$

$36+4y-y^2=4$

$y^2-4y-32=0$

$y^2-8y+4y-32=0$

$y(y-8)+4(y-8)=0$

$(y-8)(y+4)=0$

$y=8,-4$

When we put y=8,

then $x-8=9\Rightarrow x=17$

When we put y=-4,

then $x-(-4)=9\Rightarrow x=5$

So, The numbers can be (17,8) and (5,-4).

#Learn more

Two numbers differ by 4. Four times the bigger exceeds the square of the smaller by 4.

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