Math, asked by mukteshmano, 9 months ago

two numbers differ by two such that one half of the greater exceeds one third of lesser by 4​

Answers

Answered by Jermany
1

Answer:

6 and 4

Step-by-step explanation:

Let the two numbers be x and y (x>y).

ATQ: x - y = 2

x/2 - y/4 = 4

OR

x - y = 2 EQ.1

2x - y = 16

By method of elimination,

3x = 18

So, x = 6.

Putting value of x in EQ.1,

6 - y = 2

So, y = 4.

Hence, the two numbers are 6 and 4.

Answered by tarunmandalcrj12
0

Answer:

6 and 4

Step-by-step explanation:

Let the two numbers be x and y (x>y).

ATQ: x - y = 2

x/2 - y/4 = 4

OR

x - y = 2 EQ.1

2x - y = 16

By method of elimination,

3x = 18

So, x = 6.

Putting value of x in EQ.1,

6 - y = 2

So, y = 4.

Hence, the two numbers are 6 and 4.

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