Math, asked by meenakshiprasanth, 1 year ago

two numbers differ by6.if their product is 72.find the sum of the two number?

Answers

Answered by mizan786
4
let one no=x
other no=x+6
accrdng to the statement..
x(x+6)=72
i.e x2(x square)+6x-72=0
 using the method splitting the middle term...
x2+6x-72=0
x2+12x-6x-72=0
takng common terms..
x(x+12-6()x+12)=0
i.e (x+12)(x-6)=0
i.e (x+12)=0 or (x-6)=0
therefor,.. x= -12 or 6
as value cannot be negative,we take the +ve value i.e 6
so x=6
substitute these values in the place of x
one no=x=6
and other no=x+6
                    =6+6=12
and sum of these 2 nos=6+12
                                     =18

u can even verify the answer
as gvn theirproduct is 72
i.e 6*12=72

so we got the ri8  answer......:)


Answered by jhangir789
1

The sum of the two number is, x= -12 or 6.

How do you find two numbers that sum and product is given?

  • If you are asked to work out the product of two or more numbers, then you need to multiply the numbers together.
  • If you are asked to find the sum of two or more numbers, then you need to add the numbers together 0.

What is the sum difference product of any two numbers?

  • The sum,difference, product of any two even numbers is always an even number.
  • There are some unique properties of different numbers.
  • Similarly, the result of some differences and product of any two even numbers will be always an even number.
  • For example, we can take two even numbers 2 and 4.

What is a sum or difference formula?

  • The difference formula for cosines states that the cosine of the difference of two angles equals the product of the cosines of the angles plus the product of the sines of the angles.
  • The sum and difference formulas can be used to find the exact values of the sine, cosine, or tangent of an angle.

According to the question;

let one no = x.

other no = x+6.

accrdng to the statement.

x(x+6) =72

i.e x2(x square)+6x-72 = 0.

using the method splitting the middle term.

x2+6x-72=0.

x2+12x-6x-72=0.

Takng common terms.

x(x+12-6()x+12) = 0.

i.e (x+12)(x-6) = 0.

i.e (x+12)=0 or (x-6) = 0.

Therefor, x= -12 or 6.

As value cannot be negative,we take the +ve value i.e 6.

So, x=6.

Substitute these values in the place of x.

one no=x=6.

and other no=x+6.

                   =6+6=12.

and sum of these 2 nos

=6+12.

=18.

You can even verify the answer as given their product is 72.

i.e 6*12=72.

Hence, The sum of the two number is, x= -12 or 6.

#SPJ2

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