Two numbers different by 4and their product is 192 find the numbers
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Answer:
Step-by-step explanation:
Let the numbers be x and y
Such that x>y
x-y=4
x=4+y
xy=192
(4+y)y=192
4y+y^2=192
y^2+4y-192=0
y^2+16y-12y-192=0
y(y+16)-12(y+16)=0
(y+16)(y-12)=0
y+16=0 or y-12=0
y=-16 or y=12
x=4+y
x=4-16 or x=4+12
x=-12 or x=16
So the numbers are -12,-16 or 16,12
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