two numbers have a product of 56 and their sum of -15 what am i
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Answered by
2
HEYA!!
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Let the Numbers be x and y.
According to the given question:
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x + y = -15 ......................(1)
From (1) y= -15 - x
x × y = 56
Put y = -15 - x
x ( -15 - x ) = 56
-15x - x^2 = 56
x^2 + 15x - 56 = 0
Using Middle Term Splitting ,
Splitting Factors : 8 and -7
x^2 + 8x - 7x -56 = 0
x ( x + 8 ) -7 ( x + 8 )
( x - 7 ) ( x + 8 )
x = 7 , -8
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Hence the Numbers are :
➡Using +ve value of x =7
7y= 56
y = 8.
➡Using negative value of X = -8
-8y = 56
y = -7
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⏪Numbers are -7 and -8 [ as per the Question ]
-----------------------------------------------------------------------------------------------------
----------
Let the Numbers be x and y.
According to the given question:
----------------------------------------------
x + y = -15 ......................(1)
From (1) y= -15 - x
x × y = 56
Put y = -15 - x
x ( -15 - x ) = 56
-15x - x^2 = 56
x^2 + 15x - 56 = 0
Using Middle Term Splitting ,
Splitting Factors : 8 and -7
x^2 + 8x - 7x -56 = 0
x ( x + 8 ) -7 ( x + 8 )
( x - 7 ) ( x + 8 )
x = 7 , -8
-----------------------------------------------------------------------------------------------------
Hence the Numbers are :
➡Using +ve value of x =7
7y= 56
y = 8.
➡Using negative value of X = -8
-8y = 56
y = -7
-----------------------------------------------------------------------------------------------------
⏪Numbers are -7 and -8 [ as per the Question ]
-----------------------------------------------------------------------------------------------------
Answered by
0
Answer:
7 and -8 is the right answer of your question.
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