Question

two numbers in the ratio are 4:7 the difference of their square is 297 find the numbers

Answer 1

Heya...
Here is your answer ---

Let the numbers be 4x and 7x respectively.

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Now, Ac/q --
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=> (7x)^2 - (4x)^2 = 297

=> 49x^2 - 16x^2 = 297

=> 33x^2 = 297

=> x^2 = 297 / 33

=> x^2 = 9

=> x = √9
= √(3 × 3)
= 3

=> x = 3
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First number = 4x = 4 × 3 = 12

Second number = 7x = 7 × 3 = 21
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CHECKING

=> (7x)^2 - (4x)^2 = 297

=> (21)^2 - (12)^2 = 297

=> 441 - 144 = 297

=> 297 = 297

Checked
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HOPE IT HELPS....!!!!

Answer 2

Let 4:7 be
4x:7x
According to question:-
(7x)²-(4x)²=297
By using identity
a²-b²=(a-b)(a+b)
(7x-4x)(7x+4x)=297
3x*11x=297
33x²=297
X²=297/33
X²=9
X²=3²
X=3
Now, no.are 4*3=12
7*3=21