Question

Two numbers m and n are in ratio 3/8 : 5/3 . By what percent is n more than m.?

Answer 1

Answer:

i think this is the right answer

Answer 2

n is 63.26 % more than m  in the given question.

Step-by-step explanation:

$\text{Two numbers are in the ratio m : n = }\frac{3}{8} : \frac{5}{3} \text{ (given)}\\\\\textbf{Multiplying both sides by 24 because denominator has 24 as LCM}\\\\\text{It becomes}\frac{3\times24}{8} : \frac{5\times24}{3}\\ \textbf{It becomes 9 : 40 = m : n}\\\\\text{It means out of 9x + 40x = 49x, 9x are m, 40x are n}$$\text{So percent of m =} \frac{9x}{49x} \times100\\\\\text{and percent of n = }\frac{40x}{49x} \times100$

$\textbf{So m= }\frac{900 }{49}\text{ percent} \\\\\textbf{and n = }\frac{4000 }{49}\text{ percent}\\\\\textbf{So n - m =}\frac{4000-900}{49} = \frac{3100}{49} = 63.26 \text{ percent\\}$$\textbf{So correct solution is =}\frac{3100}{49}\text{ = 63.26 percent}$