Two numbers N1 and N2 when divided by 6 leave remainder 2 and 4 ,respectively. what will be the remainder when N1 - N2 is divided by 6.
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Answer:
according to my knowledge
the question is wrong because N1 is smaller than N2 so,the question will be N2 -N1 not N1 -N2 ..
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Therefore the remainder is '4' when N₁ - N₂ is divided by 6.
Given:
2 numbers N₁ and N₂ when divided by 6 leave the remainder 2 and 4, respectively.
To Find:
The value of the remainder when N₁ - N₂ is divided by 6.
Solution:
The given question can be solved as shown below.
Let us assume some number in place of N₁ and N₂.
Let N₁ = 38 so that the remainder is '2' when divided by '6'.
Let N₂ = 22 so that the remainder is '4' when divided by '6'.
Now N₁ - N₂ = 38 - 22 = 16
When N₁ - N₂ = 16 is divided by '6', the remainder is '4'.
Therefore the remainder is '4' when N₁ - N₂ is divided by 6.
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