Two numbers p and q are such that the equation px2 + 3x + 2q = 0 has – 6 as the sum of roots and as the product of roots, then find the values of p and q
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Step-by-step explanation:
px² + 3x + 2q = 0
(coefficient of x²) a = p
(coefficient of x) b = 3
(constant term) c = 2q
given
sum of the roots = -6
product of the roots = -6
-b/a = sum
-3/p = -6
p = -3/-6
p = 1/2
c/a = product
2q/p = -6
2q/1/2 = -6
2q x 2 = -6
4q = -6
q = -3/2
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