Question

two numbers such that one of them exceeds the other by 18 and their sum is 92

Answer 1

Solution :

Since, one number exceeds the other by 18, let the numbers are x and x+18.

Now, sum of the numbers = 92

=> x + (x + 18) = 92

=> 2x + 18 = 92

=> 2x = 92 - 18

=> 2x = 74

=> x = 37

So, the required numbers are

37 and (37 + 18)

i.e., 37 and 55

[Ans.]

Answer 2

Hii friend,

Let the number be Z

Then the other number will be Z+18

A/Q,

Z+ Z+ 18 = 92

2Z + 18 = 92

2Z = 92-18

2Z = 74

Z= 74/2

Z = 37

Therefore,

First Number = Z = 37

Other Number = Z+18 = 37+18 = 55

HOPE IT WILL HELP YOU...... :-)