Question

Two numbers sum is 200. If their H.C.F. is 16, the how many pairs are possible?
(a) 2 (b) 3 (c) 4 (d) None of these
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Answer 1

Answer:

d

Step-by-step explanation:

16x and 16y because it has HCF=16

16x+16y=200

16(x+y)=200

x+y=200/16=25/2

x+y=12.5

so none of these will be the answer