Question

Two numbers which differ by 3 and have a product of 88. Find them​

Answer 1

Answer:

let x, x+3 be two numbers

then,

x(x+3)=88

x^2+3x-88=0 -88=11×(-8)

=x^2+11x-8x-88=0 3=11-8

=x(x+11) -8(x+11)=0

=(x+11) (x-8)=0

x= -11 or x=8

verification: 8×(8+3)=8×11=88

-11×(-11+3)=-11×-8=88