Question

Two numbers which on multiplying gives 2000 as product and on adding gives 5 as sum.​

Answer 1

Answer:

Let first number be x

And

Another be y

ATQ

X + y = 5

X = 5 - y

Put this in (1)

XY = 2000 .....(1)

(5-y)(y) = 2000

5y - y² = 2000

Y² - 5y + 2000 = 0

Solve this you will get your answer.

If this equation couldn't be solved do there is no such numbers who satisfy above question.

Hope this will help you.