Question

two numbers whose sum is 33 and product is 260​

Answer 1

Answer:

let the two no. be x and y

given :- x+y =33 and xy =260

solution:- first we have to find x^2 + y^2

x^2 + y^2 = (x+y)^2 - 2xy

x^2 + y^2 = (33^2) - (2×260)

x^2 + y^2 = 1089-560

x^2 + y^2 = 569

now we have to find (x-y)

to find (x-y) we first have to find (x-y)^2

(x-y)^2 = (x^2 + y^2)-(2xy)

(x-y)^2 = 569-520

(x-y)^2 = 49

x-y = √49

x-y = 7

we find the value of x-y

now we find the value of x and y

(x+y)+(x-y)=33+7

x+y+x-y=40

2x=40

x=40÷2

x=20 answer

we find the value of x now we can find the value of y easily

x+y=33

20+y=33

y=33-20

y=13 answer

so the two no. are 20 and 13

Hope it will be helpful