Two object each of mass 1.5 kg are moving in the same direction line but opposite directions.The velocity of cart object is 2.5m/s before the collision during which they stick together.what will be the velocity of the covered object after collision?
Answers
Let us see the information already given in the question.
Mass of object 1 before collision = 1.5 kg
Mass of object 2 moving in opposite direction before collision = 1.5 kg
Velocity of object 1 before collision = 2.5 m s-1
Velocity of object 2 moving in opposite direction before collision = -2.5 m s-1
After collision,
Object 1 sticks to object 2
So, the total mass of the combination = m1+m2
= 1.5 + 1.5 = 3 kg
Let us consider that the velocity of the combination becomes v.
Then, according to the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
So, m1v1 + m2v2 = (m1+m2)v
That is, (1.5 * 2.5) + (1.5 * -2.5) = 3 * v
3.75 – 3.75 = 3v
Therefore, v = 0 m/s
Thus the velocity of the objects after sticking is 0 m/s.
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Answer:
Explanation:
Given :-
Mass of object 1, m₁ = 1.5 kg
Mass of object 2, m₂ = 1.5 kg
Velocity of object 1, u₁ = 2.5 m/s
Velocity of object 2, u₂ = −2.5 m/s
To Find :-
Velocity of the combined object after collision.
Formula to be used :-
Conservation of momentum
Solution :-
The objects stick together
Here, mass combined together
= m₁ + m₂
= 1.5 + 1.5
= 3 kg
Finding momentum before and after collision :-
Momentum before Momentum = Momentum of Object (1 + 2)
= 1.5 × 2.5 + 1.5 × (−2.5)
= 1.5 × 2.5 – 1.5 × 2.5
= 0
Momentum after Momentum
= Total Mass × Velocity After
= 3 × v
= 3v
law of conservation of momentum :-
Total momentum before collision = Total momentum after collision
0 = 3v
v = 0/3
v = 0 m/s
Hence, the velocity of the combined object after collision is 0 m/s.